Calcium phosphide reacts with water to form $Ca(OH)_2$ and $X$. When $X$ is passed into $CuSO_4$ solution,$Y$ and $H_2SO_4$ are formed. What is $Y$?

  • A
    $[Cu(PH_3)_4]^{2+}$
  • B
    $[Cu(PH_3)_6]^{2+}$
  • C
    $Cu_3P_2$
  • D
    $CuHPO_4$

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