(C) The reaction between calcium carbide $(CaC_2)$ and heavy water $(D_2O)$ is a hydrolysis reaction.$CaC_2 + 2D_2O \to Ca(OD)_2 + C_2D_2$Thus,the pro

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(C) The reaction between calcium carbide $(CaC_2)$ and heavy water $(D_2O)$ is a hydrolysis reaction.$CaC_2 + 2D_2O \to Ca(OD)_2 + C_2D_2$Thus,the products are calcium deuteroxide $(Ca(OD)_2)$ and deuteroacetylene $(C_2D_2)$.Among the given options,$Ca(OD)_2$ is the correct product.

Class 11 Chemistry Hydrogen Water or hydride of oxygen

Medium

Calcium carbide + heavy water $\to$ ?
The product of the above reaction is

A
$C_2H_2$
B
$CaD_2$
C
$Ca(OD)_2$
D
$CD_4$

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Class 11

Chemistry Questions

Chapter

Hydrogen

Subtopic

Water or hydride of oxygen

Describe the usefulness of water in the biosphere and biological systems.

Medium

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Water does not produce $CO$ on reacting with:

MediumJEE MAIN 2021

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Match the following methods for treating hardness of water with their corresponding reagents used.
List-$I$ List-$II$
$A$. Treatment with washing soda $I$. $Ca(OH)_2$
$B$. Calgon's method $II$. $Na_2CO_3$
$C$. Clark's method $III$. $NaAlSiO_4$
$D$. Zeolite/permutit process $IV$. $Na_6P_6O_{18}$

The correct match is:

List-$I$	List-$II$
$A$. Treatment with washing soda	$I$. $Ca(OH)_2$
$B$. Calgon's method	$II$. $Na_2CO_3$
$C$. Clark's method	$III$. $NaAlSiO_4$
$D$. Zeolite/permutit process	$IV$. $Na_6P_6O_{18}$

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