According to the corpuscular theory of light,which of the following phenomena can be explained?

  • A
    Refraction
  • B
    Interference
  • C
    Diffraction
  • D
    Polarisation

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Match Column-$1$ with Column-$2$ when a wave propagating in a denser medium enters a rarer medium:
Column-$1$ Column-$2$
$(a)$ Speed $(i)$ Increases
$(b)$ Its amplitude $(ii)$ Decreases
$(iii)$ Remains constant

Which colour of the light has the longest wavelength?

$A$ white screen illuminated by green and red light appears to be

Column $I$ shows four situations of standard Young's double slit arrangement with the screen placed far away from the slits $S_1$ and $S_2$. In each of these cases $S_1 P_0 = S_2 P_0$,$S_1 P_1 - S_2 P_1 = \lambda / 4$ and $S_1 P_2 - S_2 P_2 = \lambda / 3$,where $\lambda$ is the wavelength of the light used. In the cases $B, C$ and $D$,a transparent sheet of refractive index $\mu$ and thickness $t$ is pasted on slit $S_2$. The thicknesses of the sheets are different in different cases. The phase difference between the light waves reaching a point $P$ on the screen from the two slits is denoted by $\delta(P)$ and the intensity by $I(P)$. Match each situation given in Column $I$ with the statement$(s)$ in Column $II$ valid for that situation.
Column $I$Column $II$
$(A)$ No sheet$(p)$ $\delta(P_0) = 0$
$(B)$ $(\mu-1)t = \lambda / 4$$(q)$ $\delta(P_1) = 0$
$(C)$ $(\mu-1)t = \lambda / 2$$(r)$ $I(P_1) = 0$
$(D)$ $(\mu-1)t = 3\lambda / 4$$(s)$ $I(P_0) > I(P_1)$
$(t)$ $I(P_2) > I(P_1)$

Red light differs from blue light in its

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