Butanone reacts with methyl magnesium bromide | vedclass

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Question

(A) The reaction of butanone $(CH_3-CO-CH_2-CH_3)$ with methyl magnesium bromide $(CH_3MgBr)$ is a nucleophilic addition reaction.The nucleophilic met

Vedclass · Accepted Answer

$CH_3-CH_2-C(OH)(CH_3)_2$

Vedclass · Answer

(A) The reaction of butanone $(CH_3-CO-CH_2-CH_3)$ with methyl magnesium bromide $(CH_3MgBr)$ is a nucleophilic addition reaction.The nucleophilic methyl group $(CH_3^-)$ from the Grignard reagent attacks the electrophilic carbonyl carbon of butanone to form an intermediate addition product $(Z)$,which is $CH_3-C(OMgBr)(CH_3)-CH_2-CH_3$.Upon subsequent hydrolysis with dilute acid $(H^+/H_2O)$,the intermediate $(Z)$ is converted into a tertiary alcohol,$2$-methylbutan$-2-$ol.The structure of $2-$methylbutan$-2-$ol is $CH_3-CH_2-C(OH)(CH_3)_2$.

Column-$I$ (Reactions)	Column-$II$ (Reagents)
$(A).$ Benzophenone $\to$ Diphenylmethane	$(1).$ $LiAlH_4$
$(B).$ Benzaldehyde $\to$ $1-$Phenylethanol	$(2).$ $DiBAL-H$
$(C).$ Cyclohexanone $\to$ Cyclohexanol	$(3).$ $Zn(Hg) / \text{Conc. } HCl$
$(D).$ Phenyl benzoate $\to$ Benzaldehyde	$(4).$ $CH_3MgBr$

Butanone reacts with methyl magnesium bromide to form an addition product $(Z)$. On hydrolysis,$(Z)$ gives:

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