Butanal with dilute NaOH gives | vedclass

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(D) Butanal $(CH_3CH_2CH_2CHO)$ contains $\alpha$-hydrogen atoms. In the presence of dilute $NaOH$,it undergoes aldol condensation. The $\alpha$-carbo

Vedclass · Accepted Answer

$CH_3-CH_2-CH_2-CH(OH)-CH(C_2H_5)-CHO$

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(D) Butanal $(CH_3CH_2CH_2CHO)$ contains $\alpha$-hydrogen atoms. In the presence of dilute $NaOH$,it undergoes aldol condensation. The $\alpha$-carbon of one butanal molecule attacks the carbonyl carbon of another butanal molecule to form a $\beta$-hydroxy aldehyde. The product formed is $2$-ethyl-$3$-hydroxyhexanal,which is $CH_3-CH_2-CH_2-CH(OH)-CH(C_2H_5)-CHO$.

Butanal with dilute $NaOH$ gives

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