Bulk modulus of water is 2 times 10^9 N/m^2. | vedclass

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(C) The formula for Bulk modulus $(K)$ is given by $K = -\frac{p}{\Delta V / V}$,where $p$ is the change in pressure and $\Delta V/V$ is the volumetri

Vedclass · Accepted Answer

$2 	imes 10^6$

Vedclass · Answer

(C) The formula for Bulk modulus $(K)$ is given by $K = -\frac{p}{\Delta V / V}$,where $p$ is the change in pressure and $\Delta V/V$ is the volumetric strain.Since we are increasing the volume,the pressure change $p$ acts as a negative pressure (tensile stress).Given: $K = 2 	imes 10^9 \ N/m^2$ and $\frac{\Delta V}{V} = 0.1 \% = 0.1 / 100 = 10^{-3}$.Substituting the values into the formula: $2 	imes 10^9 = \frac{p}{10^{-3}}$.Therefore,$p = 2 	imes 10^9 	imes 10^{-3} = 2 	imes 10^6 \ N/m^2$.

Bulk modulus of water is $2 \times 10^9 \ N/m^2$. The pressure required to increase the volume of water by $0.1 \%$ in $N/m^2$ is:

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