Bromination of $(E)-2$-butenedioic acid gives:

Assertion $(A)$: Propene on addition with hydrogen bromide in the presence of peroxide gives $1-$bromopropane as the major product.
Reason $(R)$: $1-$bromopropane is the major product because it is formed through the stable carbocation.
The correct answer is

The chemical reaction is shown below:
$C_6H_5-CH_2-CH=CH_2 + HCl \rightarrow X$,$X$ is:

The reaction conditions used for converting $1, 2-$dibromoethane to ethene are

Ozonolysis of compound $X$ followed by reduction yields two moles of the same aldehyde. What is $X$?

The intermediate during the addition of $HCl$ to propene in the presence of peroxide is