Both male and female have normal vision thoug | vedclass

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(A) Colour blindness is an $X$-linked recessive trait.Since the fathers of both the male and female were colour blind,the male received his $Y$ chromo

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(A) Colour blindness is an $X$-linked recessive trait.Since the fathers of both the male and female were colour blind,the male received his $Y$ chromosome from his father and his $X$ chromosome from his mother. Since the mother did not have the gene,the male is $XY$ (normal).The female received one $X$ chromosome from her colour-blind father $(X^c)$ and one $X$ chromosome from her mother. Since the female has normal vision,she must be a carrier $(X^c X)$.When a normal male $(XY)$ marries a carrier female $(X^c X)$,the possible genotypes for their daughters are $XX$ (normal) and $X^c X$ (carrier).None of the daughters will be colour blind $(X^c X^c)$,because the father is normal and does not pass the recessive gene to his daughters.Therefore,the probability of their daughter becoming colour blind is $0 \%$.

Both male and female have normal vision though their fathers were colour blind,and mothers did not have any gene for colour blindness. The probability of their daughter becoming colour blind is (in $\%$)

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