(A) The frequency of light remains constant when it travels from one medium to another. The frequency $f$ is given by the formula $f = \frac{c}{\lambd

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(A) The frequency of light remains constant when it travels from one medium to another. The frequency $f$ is given by the formula $f = \frac{c}{\lambda}$, where $c$ is the speed of light in a vacuum and $\lambda$ is the wavelength in a vacuum. Given: $c = 3 \times 10^8 \ m \ s^{-1}$ and $\lambda = 450 \times 10^{-9} \ m$. Substituting the values: $f = \frac{3 \times 10^8}{450 \times 10^{-9}} = \frac{3 \times 10^8}{4.5 \times 10^{-7}} = \frac{3}{4.5} \times 10^{15} = 0.666... \times 10^{15} \ Hz = 6.67 \times 10^{14} \ Hz$. Since frequency is independent of the medium, the frequency in the medium is the same as in the vacuum.

Class 12 Physics Ray Optics and Optical Instruments Refraction of Light

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Blue light travelling in a vacuum has a wavelength of $450 \ nm$. It enters a medium whose refractive index is $1.5$. What is its frequency in the medium? $(Speed of light in vacuum = 3 \times 10^8 \ m \ s^{-1})$

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A
$6.67 \times 10^{14} \ Hz$
B
$10^{15} \ Hz$
C
$4.45 \times 10^{14} \ Hz$
D
$10^{14} \ Hz$

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Blue light travelling in a vacuum has a wavelength of $450 \ nm$. It enters a medium whose refractive index is $1.5$. What is its frequency in the medium? $(Speed of light in vacuum = 3 \times 10^8 \ m \ s^{-1})$

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