Benzylamine is a stronger base than aniline b | vedclass

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(A) In aniline $(C_6H_5NH_2)$,the lone pair of electrons on the nitrogen atom is in conjugation with the benzene ring and is delocalised due to resona

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the lone pair of electrons on the nitrogen atom in aniline is delocalised

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(A) In aniline $(C_6H_5NH_2)$,the lone pair of electrons on the nitrogen atom is in conjugation with the benzene ring and is delocalised due to resonance. This makes the lone pair less available for protonation,resulting in lower basicity.In benzylamine $(C_6H_5CH_2NH_2)$,the lone pair of electrons on the nitrogen atom is not involved in resonance with the benzene ring because the nitrogen atom is separated from the ring by a $CH_2$ group. Thus,the lone pair is more available for protonation,making benzylamine a stronger base than aniline.

Benzylamine is a stronger base than aniline because

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