The reaction of benzene with CH_2Cl_2 in the | vedclass

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(C) The reaction of benzene with dichloromethane $(CH_2Cl_2)$ in the presence of a Lewis acid catalyst like $AlCl_3$ is a Friedel-Crafts alkylation re

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Diphenylmethane

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(C) The reaction of benzene with dichloromethane $(CH_2Cl_2)$ in the presence of a Lewis acid catalyst like $AlCl_3$ is a Friedel-Crafts alkylation reaction.Since $CH_2Cl_2$ has two chlorine atoms,it can react with two molecules of benzene to form diphenylmethane $(C_6H_5-CH_2-C_6H_5)$ as the final product.The balanced chemical equation is:$2C_6H_6 + CH_2Cl_2 \xrightarrow{AlCl_3} C_6H_5-CH_2-C_6H_5 + 2HCl$Therefore,the product $A$ is diphenylmethane.

The reaction of benzene with $CH_2Cl_2$ in the presence of $AlCl_3$ gives product $A$. Identify $A$.

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