Beats are produced by two waves y_1 = a sin(1 | vedclass

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(C) The general equation for a wave is $y = a \sin(2\pi n t)$,where $n$ is the frequency.For the first wave,$y_1 = a \sin(1000\pi t)$,we have $2\pi n_

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$1$

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(C) The general equation for a wave is $y = a \sin(2\pi n t)$,where $n$ is the frequency.For the first wave,$y_1 = a \sin(1000\pi t)$,we have $2\pi n_1 = 1000\pi$,which gives $n_1 = 500 	ext{ Hz}$.For the second wave,$y_2 = a \sin(998\pi t)$,we have $2\pi n_2 = 998\pi$,which gives $n_2 = 499 	ext{ Hz}$.The beat frequency is the difference between the two frequencies: $n_b = |n_1 - n_2| = |500 - 499| = 1 	ext{ Hz}$.Therefore,the number of beats heard per second is $1$.

Beats are produced by two waves $y_1 = a \sin(1000\pi t)$ and $y_2 = a \sin(998\pi t)$. The number of beats heard per second is:

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