Balance the following equation: XeF_{6} + H_{ | vedclass

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Question

(B) To balance the chemical equation $XeF_{6} + H_{2}O \rightarrow XeO_{2}F_{2} + HF$:$1$. Balance the oxygen atoms: There are $2$ oxygen atoms in $Xe

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$XeF_{6} + 2 H_{2}O \rightarrow XeO_{2}F_{2} + 4 HF$

Vedclass · Answer

(B) To balance the chemical equation $XeF_{6} + H_{2}O \rightarrow XeO_{2}F_{2} + HF$:$1$. Balance the oxygen atoms: There are $2$ oxygen atoms in $XeO_{2}F_{2}$,so we need $2 H_{2}O$ on the reactant side.$2$. Balance the hydrogen atoms: With $2 H_{2}O$,there are $4$ hydrogen atoms,so we need $4 HF$ on the product side.$3$. Check the fluorine atoms: There are $6$ fluorine atoms in $XeF_{6}$ and $2$ in $XeO_{2}F_{2} + 4 HF$ $(2 + 4 = 6)$.$4$. The balanced equation is $XeF_{6} + 2 H_{2}O \rightarrow XeO_{2}F_{2} + 4 HF$.

Balance the following equation: $XeF_{6} + H_{2}O \rightarrow XeO_{2}F_{2} + HF$

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