Average density of the earth

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Question

$g = \frac{{GM}}{{{R^2}}} = \frac{{Gho  	imes V}}{{{R^2}}} \Rightarrow g = \frac{{G 	imes ho  	imes \frac{4}{3}\pi {R^3}}}{{{R^2}}}$

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is directly proportional to $g$

Vedclass · Answer

$g = \frac{{GM}}{{{R^2}}} = \frac{{Gho  	imes V}}{{{R^2}}} \Rightarrow g = \frac{{G 	imes ho  	imes \frac{4}{3}\pi {R^3}}}{{{R^2}}}$

$g = \frac{4}{3}ho \pi G.R\,\,\,\,\,where\,\,ho  	o average\,density$

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