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(C) The resistance of a conductor at temperature $t$ is given by the formula: $R_t = R_0(1 + \alpha t)$.Here, $R_t$ is the resistance at temperature $

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$500$

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(C) The resistance of a conductor at temperature $t$ is given by the formula: $R_t = R_0(1 + \alpha t)$.Here, $R_t$ is the resistance at temperature $t$, $R_0$ is the resistance at $0^{\circ}C$, and $\alpha$ is the temperature coefficient of resistance.Given that $R_t = 3R_0$ and $\alpha = 4 	imes 10^{-3} \,^{\circ}C^{-1}$.Substituting these values into the formula:$3R_0 = R_0(1 + 4 	imes 10^{-3} 	imes t)$$3 = 1 + 4 	imes 10^{-3} 	imes t$$2 = 4 	imes 10^{-3} 	imes t$$t = \frac{2}{4 	imes 10^{-3}} = \frac{2000}{4} = 500^{\circ}C$.Therefore, the resistance becomes three times its initial value at $500^{\circ}C$.

At what temperature will the resistance of a copper wire become three times its value at $0^{\circ}C$? (Temperature coefficient of resistance for copper = $4 \times 10^{-3} \,^{\circ}C^{-1}$)

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