At what rate should a single conductor cut th | vedclass

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(D) According to Ohm's law, the induced electromotive force $(e)$ is given by $e = I 	imes R$. Given: Current $(I)$ = $1.5 \, mA = 1.5 	imes 10^{-3}

Vedclass · Accepted Answer

$7.5 	imes 10^{-3} \, Wb/s$

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(D) According to Ohm's law, the induced electromotive force $(e)$ is given by $e = I 	imes R$. Given: Current $(I)$ = $1.5 \, mA = 1.5 	imes 10^{-3} \, A$ and Resistance $(R)$ = $5 \, \Omega$. Substituting the values, we get $e = (1.5 	imes 10^{-3} \, A) 	imes (5 \, \Omega) = 7.5 	imes 10^{-3} \, V$. According to Faraday's law of electromagnetic induction, the induced emf is equal to the rate of change of magnetic flux, i.e., $e = \frac{d\phi}{dt}$. Therefore, the rate at which the conductor cuts the magnetic flux is $\frac{d\phi}{dt} = 7.5 	imes 10^{-3} \, Wb/s$.

At what rate should a single conductor cut the magnetic flux so that a current of $1.5 \, mA$ flows through it when a resistance of $5 \, \Omega$ is connected across its ends?

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