At time t=0, a magnetic field of 1000 ; text{ | vedclass

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(C) The area of the loop can be calculated by subtracting the area of the two triangular cutouts from the area of the rectangle.The total area $A = (1

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$56$

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(C) The area of the loop can be calculated by subtracting the area of the two triangular cutouts from the area of the rectangle.The total area $A = (16 \; 	ext{cm} 	imes 4 \; 	ext{cm}) - 2 	imes (\frac{1}{2} 	imes 2 \; 	ext{cm} 	imes 4 \; 	ext{cm}) = 64 \; 	ext{cm}^2 - 8 \; 	ext{cm}^2 = 56 \; 	ext{cm}^2 = 56 	imes 10^{-4} \; 	ext{m}^2$.The rate of change of the magnetic field is $\frac{dB}{dt} = \frac{B_f - B_i}{\Delta t} = \frac{500 - 1000}{5} \; 	ext{Gauss/s} = -100 \; 	ext{Gauss/s} = -100 	imes 10^{-4} \; 	ext{T/s}$.The magnitude of the induced $EMF$ is given by $\varepsilon = |\frac{d\Phi}{dt}| = |A \frac{dB}{dt}|$.$\varepsilon = (56 	imes 10^{-4} \; 	ext{m}^2) 	imes (100 	imes 10^{-4} \; 	ext{T/s}) = 5600 	imes 10^{-8} \; 	ext{V} = 56 	imes 10^{-6} \; 	ext{V} = 56 \; \mu 	ext{V}$.

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