(A) Reaction: $2AB_{2(g)} \rightleftharpoons 2AB_{(g)} + B_{2(g)}$Initial moles: $1, 0, 0$Equilibrium moles: $1-x, x, \frac{x}{2}$Total moles: $1 - x

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(A) Reaction: $2AB_{2(g)} \rightleftharpoons 2AB_{(g)} + B_{2(g)}$Initial moles: $1, 0, 0$Equilibrium moles: $1-x, x, \frac{x}{2}$Total moles: $1 - x + x + \frac{x}{2} = 1 + \frac{x}{2}$Since $x \ll 1$,total moles $\approx 1$.Partial pressures:$p_{AB_2} = \frac{1-x}{1+x/2} P \approx P$$p_{AB} = \frac{x}{1+x/2} P \approx xP$$p_{B_2} = \frac{x/2}{1+x/2} P \approx \frac{x}{2} P$$K_p = \frac{(p_{AB})^2 (p_{B_2})}{(p_{AB_2})^2} = \frac{(xP)^2 (xP/2)}{P^2} = \frac{Px^3}{2}$

Class 11 Chemistry 6-1.Equilibrium (Chemical Equilibrium)Degree of dissociation and Vapour density

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At temperature,$T$,a compound $AB_{2(g)}$ dissociates according to the reaction; $2AB_{2(g)} \rightleftharpoons 2AB_{(g)} + B_{2(g)}$ with a degree of dissociation $x$,which is small compared with unity. The expression for $K_p$,in terms of $x$ and the total pressure,$P$ is

A
$\frac{Px^3}{2}$
B
$\frac{Px^2}{3}$
C
$\frac{Px^3}{3}$
D
$\frac{Px^2}{2}$

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6-1.Equilibrium (Chemical Equilibrium)

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Degree of dissociation and Vapour density

The vapour density of $PCl_5$ is $104.16$,but when heated to $230 \, ^\circ C$,its vapour density decreases to $62$. What is the degree of dissociation of $PCl_5$ at this temperature (in $\%$) ?

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At $T \, ^\circ C$,the vapour density of $PCl_5$ is $104.25$. The degree of dissociation of $PCl_5$ is ....$\%$

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For a $10^{-2} \ M \ HCN$ solution with $[H^+] = 10^{-3} \ M$,find the value of the degree of dissociation in percentage. (in $\%$)

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The vapour density of undecomposed $N_2O_4$ is $46$. When heated,the vapour density decreases to $24.5$ due to its dissociation into $NO_{2(g)}$. The percentage dissociation of $N_2O_4$ is:

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The equation $\alpha = \frac{D - d}{(n - 1)d}$ represents the degree of dissociation. For which of the following reactions is this equation valid,where $D$ is the theoretical vapour density and $d$ is the observed vapour density?

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At temperature,$T$,a compound $AB_{2(g)}$ dissociates according to the reaction; $2AB_{2(g)} \rightleftharpoons 2AB_{(g)} + B_{2(g)}$ with a degree of dissociation $x$,which is small compared with unity. The expression for $K_p$,in terms of $x$ and the total pressure,$P$ is

Similar Questions

The vapour density of $PCl_5$ is $104.16$,but when heated to $230 \, ^\circ C$,its vapour density decreases to $62$. What is the degree of dissociation of $PCl_5$ at this temperature (in $\%$) ?

At $T \, ^\circ C$,the vapour density of $PCl_5$ is $104.25$. The degree of dissociation of $PCl_5$ is ....$\%$

For a $10^{-2} \ M \ HCN$ solution with $[H^+] = 10^{-3} \ M$,find the value of the degree of dissociation in percentage. (in $\%$)

The vapour density of undecomposed $N_2O_4$ is $46$. When heated,the vapour density decreases to $24.5$ due to its dissociation into $NO_{2(g)}$. The percentage dissociation of $N_2O_4$ is:

The equation $\alpha = \frac{D - d}{(n - 1)d}$ represents the degree of dissociation. For which of the following reactions is this equation valid,where $D$ is the theoretical vapour density and $d$ is the observed vapour density?

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