At room temperature,the average speed of heli | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The average speed $(V_{avg})$ of a gas is given by the formula: $V_{avg} = \sqrt{\frac{8RT}{\pi M}}$.Since $R$,$T$,and $\pi$ are constant at a giv

Vedclass · Accepted Answer

$2 \sqrt{2}$

Vedclass · Answer

(A) The average speed $(V_{avg})$ of a gas is given by the formula: $V_{avg} = \sqrt{\frac{8RT}{\pi M}}$.Since $R$,$T$,and $\pi$ are constant at a given temperature,the average speed is inversely proportional to the square root of the molar mass $(M)$: $V_{avg} \propto \frac{1}{\sqrt{M}}$.For helium $(He)$ and oxygen $(O_2)$: $M_{He} = 4 \ g/mol$ and $M_{O_2} = 32 \ g/mol$.The ratio of their average speeds is: $\frac{V_{He}}{V_{O_2}} = \sqrt{\frac{M_{O_2}}{M_{He}}} = \sqrt{\frac{32}{4}} = \sqrt{8} = 2 \sqrt{2}$.Thus,the average speed of helium is higher than that of oxygen by a factor of $2 \sqrt{2}$.

At room temperature,the average speed of helium is higher than that of oxygen by a factor of

Similar Questions

The $RMS$ speed of $SO_2$ is the same as that of $O_2$ at $303 \, K$. This speed will be achieved at a temperature of .......... $K$.

What is the relationship between the most probable speed $(\alpha)$,average speed $(v)$,and root mean square speed $(u)$?

The rms velocity $u_{rms}$,mean velocity $u_{av}$ and most probable velocity $u_{mp}$ of a gas differ from each other at a given temperature. Which of the following ratios regarding them is correct?

At $133.33 \ K$,the $RMS$ velocity of an ideal gas is $(M = 0.083 \ kg \ mol^{-1}; R = 8.3 \ J \ mol^{-1} \ K^{-1})$ (in $m \ s^{-1}$)

Points $I$,$II$ and $III$ in the following plot respectively correspond to ($V_{mp}:$ most probable velocity).

Vedclass Test Series

Exam Paper Generator

Online Exam Module