At one time,the number of cheetahs in a habit | vedclass

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(A) The population density $(N_{t+1})$ at time $t+1$ is calculated using the formula: $N_{t+1} = N_t + [(B + I) - (D + E)]$ Where: $N_t$ = Initial pop

Vedclass · Accepted Answer

$85$

Vedclass · Answer

(A) The population density $(N_{t+1})$ at time $t+1$ is calculated using the formula: $N_{t+1} = N_t + [(B + I) - (D + E)]$ Where: $N_t$ = Initial population = $80$ $B$ = Birth rate = $4$ $I$ = Immigration = $6$ $D$ = Death rate = $2$ $E$ = Emigration = $3$ Substituting the values: $N_{t+1} = 80 + [(4 + 6) - (2 + 3)]$ $N_{t+1} = 80 + [10 - 5]$ $N_{t+1} = 80 + 5 = 85$ Therefore,the population density is $85$.

At one time,the number of cheetahs in a habitat is $80$. Their birth rate is $4$ and death rate is $2$. Among them,$6$ cheetahs are internal migrants (immigration) and $3$ cheetahs are migratory (emigration). Calculate the population density of cheetahs in that habitat.

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