At NTP,the mass of one litre of air is 1.293 | vedclass

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Question

(A) At $NTP$ (Normal Temperature and Pressure),the standard conditions are:Pressure $P = 1.013 	imes 10^5 \; Pa$Temperature $T = 273.15 \; K$Volume $

Vedclass · Accepted Answer

$0.29$

Vedclass · Answer

(A) At $NTP$ (Normal Temperature and Pressure),the standard conditions are:Pressure $P = 1.013 	imes 10^5 \; Pa$Temperature $T = 273.15 \; K$Volume $V = 1 \; L = 10^{-3} \; m^3$Mass $m = 1.293 \; g = 1.293 	imes 10^{-3} \; kg$Using the ideal gas equation $PV = m R_{specific} T$,where $R_{specific}$ is the specific gas constant:$R_{specific} = \frac{PV}{mT}$$R_{specific} = \frac{(1.013 	imes 10^5 \; Pa) 	imes (10^{-3} \; m^3)}{(1.293 	imes 10^{-3} \; kg) 	imes (273.15 \; K)}$$R_{specific} \approx \frac{101.3}{0.3531} \approx 287 \; J/(kg \cdot K)$Since the question asks for the unit $J/(K \cdot g)$,we convert $kg$ to $g$:$R_{specific} = \frac{287 \; J}{1000 \; g \cdot K} = 0.287 \; J/(K \cdot g) \approx 0.29 \; J/(K \cdot g)$.

At $NTP$,the mass of one litre of air is $1.293 \; g$. The value of the specific gas constant will be ...... $J/(K \cdot g)$.

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