At T K,two liquids A and B form an ideal sol | vedclass

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(C) Given: $P_{A}^0 = 400 \ mm \ Hg$,$P_{B}^0 = 600 \ mm \ Hg$,$x_{B} = 0.3$. Since $x_{A} + x_{B} = 1$,$x_{A} = 1 - 0.3 = 0.7$. Partial pressure of $

Vedclass · Accepted Answer

$0.609, 0.391$

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(C) Given: $P_{A}^0 = 400 \ mm \ Hg$,$P_{B}^0 = 600 \ mm \ Hg$,$x_{B} = 0.3$. Since $x_{A} + x_{B} = 1$,$x_{A} = 1 - 0.3 = 0.7$. Partial pressure of $A$ is $P_{A} = P_{A}^0 x_{A} = 400 	imes 0.7 = 280 \ mm \ Hg$. Partial pressure of $B$ is $P_{B} = P_{B}^0 x_{B} = 600 	imes 0.3 = 180 \ mm \ Hg$. Total pressure $P_{T} = P_{A} + P_{B} = 280 + 180 = 460 \ mm \ Hg$. In the vapour phase,mole fraction $y_{i} = \frac{P_{i}}{P_{T}}$. For $A$: $y_{A} = \frac{280}{460} \approx 0.609$. For $B$: $y_{B} = \frac{180}{460} \approx 0.391$.

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