At $200^{\circ} C$,nitric oxide reacts with oxygen to form nitrogen dioxide as follows: $2 NO(g) + O_2(g) \rightleftharpoons 2 NO_2(g)$,$K_C = 3 \times 10^6$. In a mixture of the three species at equilibrium,we can accurately predict that:

• A
  The concentration of both $NO$ and $O_2$ will be much larger than the concentration of $NO_2$.
• B
  The concentrations of both $NO_2$ and $O_2$ will be equal to the concentration of $NO$.
• C
  The concentrations of either $NO$ or $O_2$ (or possibly both) will be much smaller than the concentration of $NO_2$.
• D
  The concentration of $O_2$ will be exactly one half the concentration of $NO$.