At $25^{\circ} C$ and $1 \ atm$ pressure,the enthalpies of combustion are as given below:
Substance $H_{2(g)}$ $C_{\text{(graphite)}}$ $C_{2}H_{6(g)}$ $\Delta_{c}H^{\Theta} / (kJ \ mol^{-1})$ $-286.0$ $-394.0$ $-1560.0$
The enthalpy of formation of ethane is ........ .
| Substance | $H_{2(g)}$ | $C_{\text{(graphite)}}$ | $C_{2}H_{6(g)}$ |
| $\Delta_{c}H^{\Theta} / (kJ \ mol^{-1})$ | $-286.0$ | $-394.0$ | $-1560.0$ |
The enthalpy of formation of ethane is ........ .
- A$+54.0 \ kJ \ mol^{-1}$
- B$-68.0 \ kJ \ mol^{-1}$
- C$-86.0 \ kJ \ mol^{-1}$
- D$+97.0 \ kJ \ mol^{-1}$
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