(C) The observed total vapour pressure $(600 \; mm \; Hg)$ is greater than the vapour pressure of either pure component ($512 \; mm \; Hg$ and $344 \;

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a mixture of $100 \; mL \; CS_{2}$ and $100 \; mL$ acetone has a volume $< 200 \; mL$

(C) The observed total vapour pressure $(600 \; mm \; Hg)$ is greater than the vapour pressure of either pure component ($512 \; mm \; Hg$ and $344 \; mm \; Hg$). This indicates that the solution exhibits a positive deviation from Raoult's law. For solutions showing positive deviation: $1$. $\Delta_{sol} H > 0$ (Endothermic process,heat is absorbed). $2$. $\Delta_{sol} V > 0$ (Volume increases,so the final volume is $> 200 \; mL$). $3$. The solute-solvent interactions are weaker than the solute-solute and solvent-solvent interactions. $4$. Raoult's law is not obeyed. Therefore,the statement that the volume is $< 200 \; mL$ is false.

Class 12 Chemistry Solutions Mix Examples of Solutions

At $35^{\circ} C$,the vapour pressure of $CS_{2}$ is $512 \; mm \; Hg$ and that of acetone is $344 \; mm \; Hg$. $A$ solution of $CS_{2}$ in acetone has a total vapour pressure of $600 \; mm \; Hg$. The false statement amongst the following is

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A
heat must be absorbed in order to produce the solution at $35^{\circ} C$
B
Raoult's law is not obeyed by this system
C
a mixture of $100 \; mL \; CS_{2}$ and $100 \; mL$ acetone has a volume $< 200 \; mL$
D
$CS_{2}$ and acetone are less attracted to each other than to themselves

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The number of pairs of solutions having the same value of osmotic pressure from the following is:
(Assume $100\%$ ionization)
$A.$ $0.500 \ M \ C_2H_5OH \ (aq)$ and $0.25 \ M \ KBr \ (aq)$
$B.$ $0.100 \ M \ K_4[Fe(CN)_6] \ (aq)$ and $0.100 \ M \ FeSO_4(NH_4)_2SO_4 \ (aq)$
$C.$ $0.05 \ M \ K_4[Fe(CN)_6] \ (aq)$ and $0.25 \ M \ NaCl \ (aq)$
$D.$ $0.15 \ M \ NaCl \ (aq)$ and $0.1 \ M \ BaCl_2 \ (aq)$
$E.$ $0.02 \ M \ KCl \cdot MgCl_2 \cdot 6H_2O \ (aq)$ and $0.05 \ M \ KCl \ (aq)$

DifficultJEE MAIN 2023

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When a solute is added to a solvent,the freezing point of the solution decreases to $1.86 \ K$. What is the value of $\Delta T_b$? $[K_f = 1.86, K_b = 0.512]$

Medium

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The difference between the boiling point and freezing point of an aqueous solution of urea containing $10.0 \ kg$ of water is $100.2372 \ ^oC$. How many grams of urea are dissolved in the solution? (Given: $K_b = 0.513 \ K \ kg \ mol^{-1}$,$K_f = 1.86 \ K \ kg \ mol^{-1}$)

Medium

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Two elements $A$ and $B$ form compounds having formula $AB_{2}$ and $AB_{4}$. When dissolved in $20 \ g$ of benzene $(C_{6}H_{6})$,$1 \ g$ of $AB_{2}$ lowers the freezing point by $2.3 \ K$ whereas $1.0 \ g$ of $AB_{4}$ lowers it by $1.3 \ K$. The molar depression constant for benzene is $5.1 \ K \ kg \ mol^{-1}$. Calculate atomic masses of $A$ and $B$.

Easy

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Assertion : If one component of a solution obeys Raoult's law over a certain range of composition,the other component will not obey Henry's law in that range.
Reason : Raoult's law is a special case of Henry's law.

MediumAIIMS 2011

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At $35^{\circ} C$,the vapour pressure of $CS_{2}$ is $512 \; mm \; Hg$ and that of acetone is $344 \; mm \; Hg$. $A$ solution of $CS_{2}$ in acetone has a total vapour pressure of $600 \; mm \; Hg$. The false statement amongst the following is

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When a solute is added to a solvent,the freezing point of the solution decreases to $1.86 \ K$. What is the value of $\Delta T_b$? $[K_f = 1.86, K_b = 0.512]$

The difference between the boiling point and freezing point of an aqueous solution of urea containing $10.0 \ kg$ of water is $100.2372 \ ^oC$. How many grams of urea are dissolved in the solution? (Given: $K_b = 0.513 \ K \ kg \ mol^{-1}$,$K_f = 1.86 \ K \ kg \ mol^{-1}$)

Assertion : If one component of a solution obeys Raoult's law over a certain range of composition,the other component will not obey Henry's law in that range.Reason : Raoult's law is a special case of Henry's law.

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Assertion : If one component of a solution obeys Raoult's law over a certain range of composition,the other component will not obey Henry's law in that range.
Reason : Raoult's law is a special case of Henry's law.