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(D) Sodium acetate is a salt of a strong base $(NaOH)$ and a weak acid $(CH_3COOH)$.The formula for the $pH$ of a salt of a strong base and a weak aci

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$9$

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(D) Sodium acetate is a salt of a strong base $(NaOH)$ and a weak acid $(CH_3COOH)$.The formula for the $pH$ of a salt of a strong base and a weak acid is given by:$pH = 7 + \frac{1}{2}pK_a + \frac{1}{2} \log c$Given:$c = 0.1 \ M = 10^{-1} \ M$$K_a = 1.0 	imes 10^{-5}$Step $1$: Calculate $pK_a$$pK_a = - \log K_a = - \log (10^{-5}) = 5$Step $2$: Calculate $\log c$$\log c = \log (10^{-1}) = -1$Step $3$: Calculate $pH$$pH = 7 + \frac{1}{2}(5) + \frac{1}{2}(-1)$$pH = 7 + 2.5 - 0.5$$pH = 9.0$

Assuming that the degree of hydrolysis is small,the $pH$ of $0.1 \ M$ solution of sodium acetate $(K_a = 1.0 \times 10^{-5})$ will be

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