Assuming that for a husband-wife couple,the c | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The probability of having a boy is $p = \frac{1}{2}$ and the probability of having a girl is $q = \frac{1}{2}$.For $n = 2$ children,we want to fin

Vedclass · Accepted Answer

$\frac{1}{2}$

Vedclass · Answer

(C) The probability of having a boy is $p = \frac{1}{2}$ and the probability of having a girl is $q = \frac{1}{2}$.For $n = 2$ children,we want to find the probability of having exactly $1$ boy and $1$ girl.Using the binomial distribution formula $P(X = k) = {}^nC_k \cdot p^k \cdot q^{n-k}$,where $n = 2$ and $k = 1$:$P(1 	ext{ boy, } 1 	ext{ girl}) = {}^2C_1 \cdot \left(\frac{1}{2}ight)^1 \cdot \left(\frac{1}{2}ight)^{2-1}$$P(1 	ext{ boy, } 1 	ext{ girl}) = 2 \cdot \frac{1}{2} \cdot \frac{1}{2} = \frac{2}{4} = \frac{1}{2}.$

Assuming that for a husband-wife couple,the chances of their child being a boy or a girl are the same,the probability of their two children being a boy and a girl is:

Similar Questions

$A$ die is thrown three times. Getting a $3$ or a $6$ is considered success. Then the probability of at least two successes is

On a multiple choice examination with three possible answers for each of the five questions,what is the probability that a candidate would get four or more correct answers just by guessing?

If the probability that a student selected at random from a particular college is good at mathematics is $0.6$,then the probability of having exactly two students who are good at mathematics in a group of $8$ students of that college is:

$A$ die is thrown $10$ times. The probability that an odd number will come up at least once is

$A$ box has $100$ pens of which $10$ are defective. The probability that out of a sample of $5$ pens drawn one by one with replacement,at most one is defective is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module