Assuming complete dissociation,the $pH$ of a $0.01 \, M$ $NaOH$ solution is equal to

How many liters of water must be added to $1 \ L$ of an aqueous $HCl$ solution with $pH = 1$ to make the $pH$ of the resulting solution equal to $2$ (in $L$)?

The gastric juice in our stomach contains enough $HCl$ to make the hydrogen ion concentration about $0.01 \, mole/litre$. The $pH$ of gastric juice is

The $pH$ of $100 \ mL$ of an aqueous solution of a strong acid is $1$. The volume of water to be added to change its $pH$ to $2$ is .......... $mL$.

$200 \ mL$ of $0.01 \ M \ HCl$ is mixed with $400 \ mL$ of $0.01 \ M \ H_{2}SO_{4}$. The $pH$ of the mixture is

When an aqueous solution of a strong acid with $pH = 5$ is mixed with an equal volume of an aqueous solution of a strong acid with $pH = 3$,what will be the $pH$ of the resulting solution?