Assume that light of wavelength 6000,mathring | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The limit of resolution of a telescope is given by the formula $\Delta 	heta = \frac{1.22 \lambda}{D}$,where $\lambda$ is the wavelength of light

Vedclass · Accepted Answer

$2.9 	imes 10^{-7} \,	ext{radians}$

Vedclass · Answer

(B) The limit of resolution of a telescope is given by the formula $\Delta 	heta = \frac{1.22 \lambda}{D}$,where $\lambda$ is the wavelength of light and $D$ is the diameter of the objective lens.Given:$\lambda = 6000\,\mathring{A} = 6000 	imes 10^{-10}\,	ext{m} = 6 	imes 10^{-7}\,	ext{m}$.$D = 100\,	ext{inch} = 100 	imes 2.54 	imes 10^{-2}\,	ext{m} = 2.54\,	ext{m}$.Substituting these values into the formula:$\Delta 	heta = \frac{1.22 	imes 6 	imes 10^{-7}}{2.54} \approx 2.88 	imes 10^{-7}\,	ext{radians}$.Rounding to the nearest provided option,we get $\Delta 	heta \approx 2.9 	imes 10^{-7}\,	ext{radians}$.

Assume that light of wavelength $6000\,\mathring{A}$ is coming from a star. What is the limit of resolution of a telescope whose objective has a diameter of $100\,\text{inch}$?

Similar Questions

Resolving power of a telescope increases when

The correct relation between limit of resolution and resolving power is

Two point white dots are $1 \ mm$ apart on a black paper. They are viewed by an eye with a pupil diameter of $3 \ mm$. Approximately,what is the maximum distance at which the dots can be resolved by the eye? (Take wavelength of light $= 500 \ nm$)

The resolving power of a microscope depends upon:

The numerical aperture of a microscope is $0.12$, and the wavelength of light used is $600 \, nm$. Then its limit of resolution will be nearly $............. \, \mu m$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module