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(A) The isoelectric point $(pI)$ of an amino acid is the $pH$ at which it exists primarily as a zwitterion,$R-CH(NH_3^+)-COO^-$.When the $pH$ of the s

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$R-CH(NH_3^+)-COOH$

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(A) The isoelectric point $(pI)$ of an amino acid is the $pH$ at which it exists primarily as a zwitterion,$R-CH(NH_3^+)-COO^-$.When the $pH$ of the solution is lower than the $pI$ $(pH The carboxylate group $(-COO^-)$ of the zwitterion acts as a base and accepts a proton $(H^+)$ to form a carboxylic acid group $(-COOH)$.Therefore,at $pH$ $1.0$,the species $R-CH(NH_3^+)-COO^-$ gains a proton to become $R-CH(NH_3^+)-COOH$.

Assume that a particular amino acid has an isoelectric point of $6.0$. In a solution at $pH$ $1.0$,which of the following species will predominate?

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