Assume each oil drop has a capacitance of $C$. If $n$ drops are combined to form a bigger drop,then the capacitance of the bigger drop $C^{\prime}$ would be

  • A
    $C^{\prime}=\frac{2 n^{1 / 3}}{3} C$
  • B
    $C^{\prime}=\frac{5 n^{1 / 3}}{4} C$
  • C
    $C^{\prime}=\frac{n^{1 / 3}}{5} C$
  • D
    $C^{\prime}=C \cdot n^{1 / 3}$

Explore More

Similar Questions

The capacity of a spherical conductor in the $MKS$ system is:

The graph shows the variation of voltage $V$ across the plates of two capacitors $A$ and $B$ versus the charge $Q$ stored in them. Then:

$A$ spherical capacitor consists of two concentric spherical conductors,held in position by suitable insulating supports. Show that the capacitance of a spherical capacitor is given by $C = \frac{4 \pi \varepsilon_{0} r_{1} r_{2}}{r_{1} - r_{2}}$,where $r_{1}$ and $r_{2}$ are the radii of outer and inner spheres,respectively.

The ratio of charge to potential of a body is known as

The capacitance of a capacitor depends on:

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo