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(A) In the given reaction: $Na_2C_2O_4 + H_2SO_4 \longrightarrow Na_2SO_4 + CO + CO_2$.The oxidation state of carbon in $Na_2C_2O_4$ is $+3$.In the pr

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for disproportionation reaction.

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(A) In the given reaction: $Na_2C_2O_4 + H_2SO_4 \longrightarrow Na_2SO_4 + CO + CO_2$.The oxidation state of carbon in $Na_2C_2O_4$ is $+3$.In the products,the oxidation state of carbon in $CO$ is $+2$ and in $CO_2$ is $+4$.Since the same element (carbon) is simultaneously oxidized (from $+3$ to $+4$) and reduced (from $+3$ to $+2$),this is a disproportionation reaction.Therefore,the correct assignment is $A$.

Assign $A, B, C, D$ from the given type of reaction.
$Na_2C_2O_4 + H_2SO_4 \text{ (conc.)} \longrightarrow Na_2SO_4 + CO + CO_2$

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Assign $A, B, C, D$ from the given type of reaction.$Na_2C_2O_4 + H_2SO_4 \text{ (conc.)} \longrightarrow Na_2SO_4 + CO + CO_2$