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(C) The given reaction is: $2NaI + MnO_2 + 2H_2SO_4 	o MnSO_4 + Na_2SO_4 + I_2 + 2H_2O$.In this reaction,the oxidation state of $I$ changes from $-1$

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for either intermolecular redox reaction or displacement reaction.

Vedclass · Answer

(C) The given reaction is: $2NaI + MnO_2 + 2H_2SO_4 	o MnSO_4 + Na_2SO_4 + I_2 + 2H_2O$.In this reaction,the oxidation state of $I$ changes from $-1$ in $NaI$ to $0$ in $I_2$ (oxidation).The oxidation state of $Mn$ changes from $+4$ in $MnO_2$ to $+2$ in $MnSO_4$ (reduction).Since two different species are undergoing oxidation and reduction,it is an intermolecular redox reaction.Also,$I^-$ is displaced by the redox process,making it a displacement reaction.Therefore,the correct classification is for either intermolecular redox reaction or displacement reaction.

Assign $A$,$B$,$C$,$D$ from the given type of reaction.
$2NaI + MnO_2 + 2H_2SO_4 \to MnSO_4 + Na_2SO_4 + I_2 + 2H_2O$

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Assign $A$,$B$,$C$,$D$ from the given type of reaction.$2NaI + MnO_2 + 2H_2SO_4 \to MnSO_4 + Na_2SO_4 + I_2 + 2H_2O$