Assertion (A): The aqueous solution of CH_3CO | vedclass

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Question

(A) $CH_3COONa$ is a salt of a weak acid $(CH_3COOH)$ and a strong base $(NaOH)$.In aqueous solution,it ionizes as: $CH_3COONa \rightleftharpoons CH_3

Vedclass · Accepted Answer

Both $(A)$ and $(R)$ are true and $(R)$ is the correct explanation of $(A)$.

Vedclass · Answer

(A) $CH_3COONa$ is a salt of a weak acid $(CH_3COOH)$ and a strong base $(NaOH)$.In aqueous solution,it ionizes as: $CH_3COONa \rightleftharpoons CH_3COO^{-} + Na^{+}$.The acetate ion $(CH_3COO^{-})$ undergoes anionic hydrolysis: $CH_3COO^{-} + H_2O \rightleftharpoons CH_3COOH + OH^{-}$.Due to the production of $OH^{-}$ ions,the solution becomes alkaline (basic).Therefore,both $(A)$ and $(R)$ are true and $(R)$ is the correct explanation of $(A)$.

Assertion $(A)$: The aqueous solution of $CH_3COONa$ is alkaline in nature. Reason $(R)$: Acetate ion undergoes anionic hydrolysis. The correct answer is

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