Assertion (A): NaCl is less soluble in heavy | vedclass

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(A) The solubility of an ionic compound like $NaCl$ depends on the dielectric constant of the solvent. Higher dielectric constant leads to better solv

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Both $(A)$ and $(R)$ are true and $(R)$ is the correct explanation of $(A)$

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(A) The solubility of an ionic compound like $NaCl$ depends on the dielectric constant of the solvent. Higher dielectric constant leads to better solvation of ions,which increases solubility.The dielectric constant of ordinary water $(H_2O)$ is approximately $81$,while that of heavy water $(D_2O)$ is approximately $80$.Since the dielectric constant of ordinary water is higher,$NaCl$ is more soluble in ordinary water than in heavy water.Therefore,both Assertion $(A)$ and Reason $(R)$ are true,and $(R)$ is the correct explanation of $(A)$.

Assertion $(A)$: $NaCl$ is less soluble in heavy water than in ordinary water.
Reason $(R)$: Dielectric constant of ordinary water is more than that of heavy water.
The correct answer is

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Assertion $(A)$: $NaCl$ is less soluble in heavy water than in ordinary water.Reason $(R)$: Dielectric constant of ordinary water is more than that of heavy water.The correct answer is