Assertion $(A)$: $S_N1$ hydrolysis of optically active $2-$bromooctane results in the formation of $(\pm)-$octan$-2-$ol.
Reason $(R)$: The reaction proceeds through a planar carbocation which can be attacked by the nucleophile from either side.
The correct answer is

  • A
    $(A)$ and $(R)$ are correct,$(R)$ is the correct explanation of $(A)$
  • B
    $(A)$ and $(R)$ are correct but $(R)$ is not the correct explanation of $(A)$
  • C
    $(A)$ is correct but $(R)$ is not correct
  • D
    $(A)$ is not correct but $(R)$ is correct

Explore More

Similar Questions

Predict the product for the following reaction:
$\xrightarrow[\Delta]{alc. \ KOH}$ product

Which of the following undergoes nucleophilic substitution exclusively by $S_N1$ mechanism?

When ethyl iodide is heated with silver nitrate,the product obtained is

Which of the following statements is correct for optically active alkyl halides,upon reaction with nucleophiles?
$S_{N}1$$S_{N}2$
$(a)$Retention of configurationInversion of configuration
$(b)$RacemisationInversion of configuration
$(c)$Inversion of configurationRetention of configuration
$(d)$RacemisationRetention of configuration

$A$ bromoalkane $X$ reacts with magnesium in dry ether to form compound $Y$. The reaction of $Y$ with methanal followed by hydrolysis yields an alcohol having molecular formula $C_{4}H_{10}O$. The compound $X$ is

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo