Assertion: One molal aqueous solution of gluc | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Molality is defined as the number of moles of solute dissolved in $1 	ext{ kg}$ of solvent.$Molality (m) = \frac{	ext{Number of moles of solute}

Vedclass · Accepted Answer

If both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion.

Vedclass · Answer

(A) Molality is defined as the number of moles of solute dissolved in $1 	ext{ kg}$ of solvent.$Molality (m) = \frac{	ext{Number of moles of solute}}{	ext{Mass of solvent in kg}}$The molar mass of glucose $(C_6H_{12}O_6)$ is $180 	ext{ g/mol}$.For a $1 	ext{ molal}$ solution,we have $1 	ext{ mole}$ of glucose in $1 	ext{ kg}$ of water.Since $1 	ext{ mole}$ of glucose $= 180 	ext{ g}$,the assertion is correct.The reason correctly defines a $1 	ext{ molal}$ solution as one containing $1 	ext{ mole}$ of solute in $1000 	ext{ g}$ $(1 	ext{ kg})$ of solvent.Therefore,the Reason is the correct explanation of the Assertion.

Assertion: One molal aqueous solution of glucose contains $180 \text{ g}$ of glucose in $1 \text{ kg}$ of water.
Reason: $A$ solution containing one mole of solute in $1000 \text{ g}$ of solvent is called a one molal solution.

Similar Questions

Let $f$ be a non-zero real-valued continuous function satisfying $f(x+y)=f(x) \cdot f(y)$ for all $x, y \in R$. If $f(2)=9$,then $f(6)$ is equal to

Identify the glycosidic linkage present in lactose.

$A$ ray of light passes through four transparent media with refractive indices $\mu_1$,$\mu_2$,$\mu_3$,and $\mu_4$ as shown in the figure. The surfaces of all media are parallel. If the emergent ray $CD$ is parallel to the incident ray $AB$,we must have

The magnetic induction at the centre of a current-carrying circular coil of radius $10 \ cm$ is $5 \sqrt{5}$ times the magnetic induction at a point on its axis. The distance of the point from the centre of the coil (in $cm$) is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Assertion: One molal aqueous solution of glucose contains $180 \text{ g}$ of glucose in $1 \text{ kg}$ of water.Reason: $A$ solution containing one mole of solute in $1000 \text{ g}$ of solvent is called a one molal solution.