Assertion : Both Be and Al can form complexes | vedclass

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(A) The electronic configuration of $Be$ is $1s^2 2s^2$. It has only $s$ and $p$ orbitals in its valence shell $(n=2)$.Since there are no vacant $d-$o

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If both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion.

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(A) The electronic configuration of $Be$ is $1s^2 2s^2$. It has only $s$ and $p$ orbitals in its valence shell $(n=2)$.Since there are no vacant $d-$orbitals available in the valence shell of $Be$,it cannot expand its coordination number beyond $4$.Therefore,$Be$ can form $BeF_4^{2-}$ but cannot form $BeF_6^{3-}$.$Al$ has $3d$ orbitals available,allowing it to form $AlF_6^{3-}$.Thus,both the assertion and the reason are correct,and the reason correctly explains why $BeF_6^{3-}$ is not formed.

Assertion : Both $Be$ and $Al$ can form complexes such as $BeF_4^{2-}$ and $AlF_6^{3-}$ respectively,$BeF_6^{3-}$ is not formed.
Reason : In case of $Be$,no vacant $d-$orbitals are present in its outermost shell.

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Assertion : Both $Be$ and $Al$ can form complexes such as $BeF_4^{2-}$ and $AlF_6^{3-}$ respectively,$BeF_6^{3-}$ is not formed.Reason : In case of $Be$,no vacant $d-$orbitals are present in its outermost shell.