(A) catalyst provides an alternate reaction pathway with a lower activation energy $(E_a)$.It speeds up both the forward and backward reactions to the

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(A) catalyst provides an alternate reaction pathway with a lower activation energy $(E_a)$.It speeds up both the forward and backward reactions to the same extent.Since the rate of both reactions increases equally,the equilibrium position remains unchanged,and the equilibrium constant $(K_{eq})$ is not altered.

Class 11 Chemistry 6-1.Equilibrium (Chemical Equilibrium)Le-Chaterlier principle and It’s application

Medium

Assertion : $A$ catalyst does not alter the equilibrium constant of a reaction.
Reason : The catalyst forms a complex with the reactants and provides an alternate path with lower energy of activation for the reaction; the forward and the backward reactions are affected to the same extent.

AIIMS 2010 All AIIMS

A
If both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion.
B
If both Assertion and Reason are correct but Reason is not a correct explanation of the Assertion.
C
If the Assertion is correct but Reason is incorrect.
D
If both the Assertion and Reason are incorrect.

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6-1.Equilibrium (Chemical Equilibrium)

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Le-Chaterlier principle and It’s application

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Assertion : $A$ catalyst does not alter the equilibrium constant of a reaction.Reason : The catalyst forms a complex with the reactants and provides an alternate path with lower energy of activation for the reaction; the forward and the backward reactions are affected to the same extent.

Similar Questions

The reaction $SO_2 + Cl_2 \rightleftharpoons SO_2Cl_2$ is exothermic. If some $SO_2$ is added to the equilibrium mixture at constant volume,then ...........

Which of the following equilibria will shift to the right side by an increase in pressure?

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Which of the following conditions is favourable for the production of ammonia by Haber's process?

For the reaction $2A_{(g)} + B_{(g)} \rightleftharpoons C_{(g)} + 362 \, kcal$,which combination of pressure and temperature will favor the formation of $C$ at equilibrium?

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Assertion : $A$ catalyst does not alter the equilibrium constant of a reaction.
Reason : The catalyst forms a complex with the reactants and provides an alternate path with lower energy of activation for the reaction; the forward and the backward reactions are affected to the same extent.