Assertion : $1, 3-$ Butadiene is the monomer for natural rubber.
Reason : Natural rubber is formed through anionic addition polymerization.
Reason : Natural rubber is formed through anionic addition polymerization.
- AIf both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion.
- BIf both Assertion and Reason are correct but Reason is not a correct explanation of the Assertion.
- CIf the Assertion is correct but Reason is incorrect.
- DIf both the Assertion and Reason are incorrect.
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Similar Questions
Match List-$I$ with List-$II$.
List-$I$ (Chemicals) List-$II$ (Use / Preparation / Constituent) $(a)$ Alcoholic potassium hydroxide $(i)$ Electrodes in batteries $(b)$ $Pd / BaSO_4$ $(ii)$ Obtained by addition reaction $(c)$ $BHC$ (Benzene hexachloride) $(iii)$ Used for $\beta$-elimination reaction $(d)$ Polyacetylene $(iv)$ Lindlar's catalyst
Choose the most appropriate match.
| List-$I$ (Chemicals) | List-$II$ (Use / Preparation / Constituent) |
|---|---|
| $(a)$ Alcoholic potassium hydroxide | $(i)$ Electrodes in batteries |
| $(b)$ $Pd / BaSO_4$ | $(ii)$ Obtained by addition reaction |
| $(c)$ $BHC$ (Benzene hexachloride) | $(iii)$ Used for $\beta$-elimination reaction |
| $(d)$ Polyacetylene | $(iv)$ Lindlar's catalyst |
Choose the most appropriate match.
Match the polymers given in Column-$I$ with their commercial names given in Column-$II$.
Column-$I$ Column-$II$ $A$. Polyester of glycol and phthalic acid $i$. Novolac $B$. Copolymer of $1,3$-butadiene and styrene $ii$. Glyptal $C$. Phenol and formaldehyde resin $iii$. Buna-$S$ $D$. Polyester of glycol and terephthalic acid $iv$. Buna-$N$ $E$. Copolymer of $1,3$-butadiene and acrylonitrile $v$. Dacron
| Column-$I$ | Column-$II$ |
| $A$. Polyester of glycol and phthalic acid | $i$. Novolac |
| $B$. Copolymer of $1,3$-butadiene and styrene | $ii$. Glyptal |
| $C$. Phenol and formaldehyde resin | $iii$. Buna-$S$ |
| $D$. Polyester of glycol and terephthalic acid | $iv$. Buna-$N$ |
| $E$. Copolymer of $1,3$-butadiene and acrylonitrile | $v$. Dacron |
Medium
View SolutionMatch List-$I$ with List-$II$.
List-$I$ List-$II$ $A$. $2$-Chloro-$1,3$-butadiene $I$. Biodegradable polymer $B$. Nylon-$2$-nylon-$6$ $II$. Synthetic Rubber $C$. Polyacrylonitrile $III$. Polyester $D$. Dacron $IV$. Addition Polymer
Choose the correct answer from the options given below:
| List-$I$ | List-$II$ |
|---|---|
| $A$. $2$-Chloro-$1,3$-butadiene | $I$. Biodegradable polymer |
| $B$. Nylon-$2$-nylon-$6$ | $II$. Synthetic Rubber |
| $C$. Polyacrylonitrile | $III$. Polyester |
| $D$. Dacron | $IV$. Addition Polymer |
Choose the correct answer from the options given below:
An organic compound $P$ with molecular formula $C_{9}H_{18}O_{2}$ decolorizes bromine water and also shows a positive iodoform test. $P$ on ozonolysis followed by treatment with $H_{2}O_{2}$ gives $Q$ and $R$. While compound $Q$ shows a positive iodoform test,compound $R$ does not. $Q$ and $R$ on oxidation with pyridinium chlorochromate $(PCC)$ followed by heating give $S$ and $T$,respectively. Both $S$ and $T$ show a positive iodoform test.
Complete copolymerization of $500$ moles of $Q$ and $500$ moles of $R$ gives one mole of a single acyclic copolymer $U$.
[Given,atomic mass: $H=1, C=12, O=16$ ]
$(1)$ Sum of the number of oxygen atoms in $S$ and $T$ is. . . . . .
$(2)$ The molecular weight of $U$ is
Give the answer for questions $(1)$ and $(2)$.
Complete copolymerization of $500$ moles of $Q$ and $500$ moles of $R$ gives one mole of a single acyclic copolymer $U$.
[Given,atomic mass: $H=1, C=12, O=16$ ]
$(1)$ Sum of the number of oxygen atoms in $S$ and $T$ is. . . . . .
$(2)$ The molecular weight of $U$ is
Give the answer for questions $(1)$ and $(2)$.
Match the chemical substances in Column-$I$ with the type of polymers/type of bonds in Column-$II$.
Column-$I$ Column-$II$ $A$. Cellulose $p$. Natural polymer $B$. Nylon-$6,6$ $q$. Synthetic polymer $C$. Protein $r$. Amide linkage $D$. Sucrose $s$. Glycoside linkage
| Column-$I$ | Column-$II$ |
| $A$. Cellulose | $p$. Natural polymer |
| $B$. Nylon-$6,6$ | $q$. Synthetic polymer |
| $C$. Protein | $r$. Amide linkage |
| $D$. Sucrose | $s$. Glycoside linkage |
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