Assertion : BaCO_3 is more soluble in HNO_3 t | vedclass

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(A) Barium carbonate $(BaCO_3)$ is a salt of a weak acid $(H_2CO_3)$ and a strong base $(Ba(OH)_2)$.In water,it has very low solubility.When $HNO_3$ i

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(A) Barium carbonate $(BaCO_3)$ is a salt of a weak acid $(H_2CO_3)$ and a strong base $(Ba(OH)_2)$.In water,it has very low solubility.When $HNO_3$ is added,the carbonate ion $(CO_3^{2-})$ acts as a weak base and reacts with $H^+$ ions from the strong acid to form $H_2CO_3$,which further decomposes into $CO_2$ and $H_2O$.This reaction removes $CO_3^{2-}$ ions from the equilibrium,shifting the dissolution equilibrium of $BaCO_3$ to the right according to Le Chatelier's principle,thereby increasing its solubility.The reaction is: $BaCO_3(s) + 2H^+(aq) 	o Ba^{2+}(aq) + CO_2(g) + H_2O(l)$.

Assertion : $BaCO_3$ is more soluble in $HNO_3$ than in plain water.
Reason : Carbonate is a weak base and reacts with the $H^+$ from the strong acid,causing the barium salt to dissociate.

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Assertion : $BaCO_3$ is more soluble in $HNO_3$ than in plain water.Reason : Carbonate is a weak base and reacts with the $H^+$ from the strong acid,causing the barium salt to dissociate.