As the temperature increases,the pH of a KOH | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The $pH$ of a solution is defined as $pH = -\log[H^+]$.For a $KOH$ solution,the ionic product of water $(K_w = [H^+][OH^-])$ increases with an inc

Vedclass · Accepted Answer

Will decrease

Vedclass · Answer

(A) The $pH$ of a solution is defined as $pH = -\log[H^+]$.For a $KOH$ solution,the ionic product of water $(K_w = [H^+][OH^-])$ increases with an increase in temperature.As $K_w$ increases,the concentration of $[H^+]$ increases,which leads to a decrease in the $pH$ value.Alternatively,$pH + pOH = pK_w$. As temperature increases,$pK_w$ decreases,and since $pOH$ is relatively stable for a strong base,$pH$ must decrease.

As the temperature increases,the $pH$ of a $KOH$ solution

Similar Questions

At $90\,^oC$,the $pH$ of a $0.1\,M$ $NaCl$ aqueous solution is .......

The $pH$ of pure water at $80^{\circ} C$ is

Ionic product of water at $310 \, K$ is $2.7 \times 10^{-14}$. What is the $pH$ of neutral water at this temperature?

When pure water is taken in a container and it absorbs $CO_2$ from the atmosphere,what will be the $pH$?

If the ionic product of water $(K_w)$ is $1.96 \times 10^{-14}$ at $35^{\circ} C$,what is its value at $10^{\circ} C$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module