As shown in the figure,a series circuit conne | vedclass

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(C) The total resistance of the circuit is $R_{total} = R_1 + R_2 = 44 \,\Omega + 36 \,\Omega = 80 \,\Omega$.The total reactance of the circuit is $X_

Vedclass · Accepted Answer

$144$

Vedclass · Answer

(C) The total resistance of the circuit is $R_{total} = R_1 + R_2 = 44 \,\Omega + 36 \,\Omega = 80 \,\Omega$.The total reactance of the circuit is $X_{total} = X_L - X_C = 90 \,\Omega - 30 \,\Omega = 60 \,\Omega$.The impedance of the circuit is $Z = \sqrt{R_{total}^2 + X_{total}^2} = \sqrt{80^2 + 60^2} = \sqrt{6400 + 3600} = \sqrt{10000} = 100 \,\Omega$.The $RMS$ current in the circuit is $I_{rms} = \frac{V_{rms}}{Z} = \frac{200 \,V}{100 \,\Omega} = 2 \,A$.The power dissipated in the coil is given by $P_{coil} = I_{rms}^2 	imes R_2$.Substituting the values,$P_{coil} = (2 \,A)^2 	imes 36 \,\Omega = 4 	imes 36 = 144 \,W$.

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