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(D) In $C_3$ plants,the synthesis of one molecule of glucose $(C_6H_{12}O_6)$ requires $18$ $ATP$ and $12$ $NADPH$ molecules.In $C_4$ plants (like mai

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$12$

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(D) In $C_3$ plants,the synthesis of one molecule of glucose $(C_6H_{12}O_6)$ requires $18$ $ATP$ and $12$ $NADPH$ molecules.In $C_4$ plants (like maize),the $C_4$ cycle requires an additional $2$ $ATP$ molecules per $CO_2$ molecule fixed for the regeneration of phosphoenolpyruvate $(PEP)$.Since $6$ molecules of $CO_2$ are required to produce one molecule of hexose sugar,the total additional $ATP$ required is $6 	imes 2 = 12$ $ATP$ molecules.Therefore,a $C_4$ plant requires $18 + 12 = 30$ $ATP$ molecules in total for the synthesis of one glucose molecule.

As compared to a $C_3$ plant,how many additional molecules of $ATP$ are needed for the net production of one molecule of hexose sugar by a maize plant?

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