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(D) In $C_{3}$ plants,the synthesis of one molecule of glucose $(C_{6}H_{12}O_{6})$ requires $18$ $ATP$ and $12$ $NADPH$ molecules.In $C_{4}$ plants,a

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$12$

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(D) In $C_{3}$ plants,the synthesis of one molecule of glucose $(C_{6}H_{12}O_{6})$ requires $18$ $ATP$ and $12$ $NADPH$ molecules.In $C_{4}$ plants,an additional $CO_{2}$ fixation cycle (the $C_{4}$ cycle) occurs to concentrate $CO_{2}$ in the bundle sheath cells.This $C_{4}$ cycle requires $2$ additional $ATP$ molecules per $CO_{2}$ molecule fixed to regenerate phosphoenolpyruvate $(PEP)$.Since $6$ molecules of $CO_{2}$ are required to produce one molecule of hexose sugar,the total additional $ATP$ required is $6 	imes 2 = 12$ $ATP$ molecules.Therefore,$C_{4}$ plants require $30$ $ATP$ $(18 + 12)$ and $12$ $NADPH$ for the synthesis of one glucose molecule.

As compared to a $C_{3}$-plant,how many additional molecules of $ATP$ are needed for the net production of one molecule of hexose sugar by $C_{4}$-plants?

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