As a result of a change in the magnetic flux linked to the closed loop as shown in the figure,an $e.m.f.$ $V$ volt is induced in the loop. The work done (in joule) in taking a charge $Q$ coulomb once along the loop is

There is a uniform magnetic field directed perpendicular and into the plane of the paper. An irregular shaped conducting loop is slowly changing into a circular loop in the plane of the paper. Then

The direction of induced current is such that it opposes the very cause that has produced it. This is the law of

$A$ coil having $n$ turns and resistance $R \, \Omega$ is connected with a galvanometer of resistance $4 \, R \, \Omega$. This combination is moved in time $t$ seconds from a magnetic field $W_1$ weber to $W_2$ weber. The induced current in the circuit is

Lenz's law applies to

$A$ coil having $100$ turns and an area of $1 \times 10^{-3} \ m^2$ is placed in a magnetic field of $1 \ Wb/m^2$. If the magnetic field is reversed,what is the total charge that flows through the circuit,given that the resistance of the circuit is $10 \ \Omega$?