Arrange the orbitals of H atom in the increas | vedclass

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(A) For a single-electron species like the $H$ atom,the energy of an orbital depends only on the principal quantum number $(n)$.Orbitals with the same

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$2s < 3s = 3p_x = 3p_y < 4s = 4p_z = 4d_{xy}$

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(A) For a single-electron species like the $H$ atom,the energy of an orbital depends only on the principal quantum number $(n)$.Orbitals with the same value of $n$ have the same energy (degenerate orbitals).Comparing the given orbitals:- For $2s$,$n = 2$.- For $3s, 3p_x, 3p_y$,$n = 3$.- For $4s, 4p_z, 4d_{xy}$,$n = 4$.Therefore,the increasing order of energy is: $2s < 3s = 3p_x = 3p_y < 4s = 4p_z = 4d_{xy}$.

Arrange the orbitals of $H$ atom in the increasing order of their energy:
$3p_x, 2s, 4d_{xy}, 3s, 4p_z, 3p_y, 4s$

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Arrange the orbitals of $H$ atom in the increasing order of their energy:$3p_x, 2s, 4d_{xy}, 3s, 4p_z, 3p_y, 4s$