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(B) The acidic strength of phenols is determined by the stability of the corresponding phenoxide ion. Electron-withdrawing groups $(EWG)$ increase aci

Vedclass · Accepted Answer

$IV > III > I > II$

Vedclass · Answer

(B) The acidic strength of phenols is determined by the stability of the corresponding phenoxide ion. Electron-withdrawing groups $(EWG)$ increase acidity by stabilizing the phenoxide ion,while electron-donating groups $(EDG)$ decrease acidity by destabilizing it.$1.$ $IV$ ($p$-nitrophenol): The $-NO_2$ group at the $p$-position exerts both a strong $-I$ effect and a strong $-M$ (mesomeric) effect,which significantly stabilizes the phenoxide ion.$2.$ $III$ ($m$-nitrophenol): The $-NO_2$ group at the $m$-position exerts only a $-I$ effect (no $-M$ effect),providing less stabilization than at the $p$-position.$3.$ $I$ (Phenol): This is the reference compound.$4.$ $II$ ($p$-methylphenol): The $-CH_3$ group at the $p$-position exerts a $+I$ effect and hyperconjugation $(+H)$,which donates electron density and destabilizes the phenoxide ion,making it the least acidic.Therefore,the correct order of acidic strength is $IV > III > I > II$.

List-$I$ (Compound)	List-$II$ ($pK_a$ value)
$A$. Ethanol	$I$. $10.0$
$B$. Phenol	$II$. $15.9$
$C$. $m$-Nitrophenol	$III$. $7.1$
$D$. $p$-Nitrophenol	$IV$. $8.3$

Arrange the following in the correct order of their acidic strength:

Similar Questions

Which of the following compounds has the least $pK_a$ value?

The major product of the following reaction sequence is:
Aniline $\xrightarrow[(i) NaNO_2, HCl, 273-278K]{(ii) H_2O, warm} \text{Product}$ $\xrightarrow[(iv) NaOH]{(iii) Br_2, (excess)} \text{Product}$ $\xrightarrow{(v) CH_3I} \text{Final Product}$

What will be the major product of the given reaction?

Match List-$I$ with List-$II$:

List-$I$ (Compound) List-$II$ ($pK_a$ value)

$A$. Ethanol $I$. $10.0$

$B$. Phenol $II$. $15.9$

$C$. $m$-Nitrophenol $III$. $7.1$

$D$. $p$-Nitrophenol $IV$. $8.3$

Choose the correct answer from the options given below:

What amount of bromine will be required to convert $2 \ g$ of phenol into $2, 4, 6-$tribromophenol (in $g$)?

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