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(A) $BF_3$ has a symmetrical trigonal planar structure,so its net dipole moment is $0 \ D$.Both $H_2O$ and $H_2S$ have a bent structure,which results

Vedclass · Accepted Answer

$BF_3 < H_2S < H_2O$

Vedclass · Answer

(A) $BF_3$ has a symmetrical trigonal planar structure,so its net dipole moment is $0 \ D$.Both $H_2O$ and $H_2S$ have a bent structure,which results in a non-zero net dipole moment.Oxygen is more electronegative than sulfur,which makes the $O-H$ bond more polar than the $S-H$ bond. Consequently,$H_2O$ has a higher dipole moment than $H_2S$.Thus,the order of increasing dipole moment is $BF_3 < H_2S < H_2O$.

Arrange the following in order of increasing dipole moment: $H_2O, H_2S, BF_3$.

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