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(B) Atomic radius generally increases down a group and decreases across a period from left to right. $Na$ $(Z=11)$ and $Mg$ $(Z=12)$ belong to the $3^

Vedclass · Accepted Answer

$Mg < Na < K < Rb$

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(B) Atomic radius generally increases down a group and decreases across a period from left to right. $Na$ $(Z=11)$ and $Mg$ $(Z=12)$ belong to the $3^{rd}$ period,while $K$ $(Z=19)$ and $Rb$ $(Z=37)$ belong to the $4^{th}$ and $5^{th}$ periods respectively. Across the $3^{rd}$ period,atomic radius decreases from $Na$ to $Mg$,so $Mg Down Group $1$,atomic radius increases as $Na Combining these trends,the order is $Mg < Na < K < Rb$.

Arrange the following elements in increasing order of their atomic radius: $Na$,$K$,$Mg$,$Rb$.

Similar Questions

Arrange the following elements in the increasing order of their atomic radii:
$(i)$ $O, N, F, B, Be, Li, C$
$(ii)$ $P, S, Mg, Na, Al, Si, Cl$
$(iii)$ $K, Na, Li, Cs, Rb$
$(iv)$ $Cl, F, I, At, Br$

Which of the following is arranged in decreasing order of size?

What is the increasing order of atomic radii for $O, C, F, Cl,$ and $Br$?

In which of the following pairs is the difference between the covalent radii of the two metals maximum?

Which of the following represents the correct order of atomic radius?

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